A wheel is making revolutions about its axis with uniform angular acceleration. Starting from rest, it reaches 100 rev/sec in 4 seconds.

Acceleration (a)=0.1ms-2 Time (t)=120seconds W k t, a) distance        S = ut+1/2 a t2           = 0+1/2 x 0.1 x 14400 = 720 m b) speed = distance/ time                   = 720 / 120                   = 6 ms-1  In this solved problem...

The distance travelled in first 8 s, x1= 0 + 1 /2 (5) (8) 2 = 160 m.  At this point the velocity v = u+ at = 0 + (5×8)...

θ = 100 π; t = 5 sec θ = 1/2 αt2 = 100 π = 1/2 α 25 α = 8π × 5 = 40 π rad/s = 20 rev/s α = 8π rad/s2 = 4 rev/s2 ω = 40π rad/s2...

Theta=wt+1/2alpha Tsq. By this we will get Theta=200. For first 10 and last 10 sec theta will be same therefore =400. And for 10 sec of middle is alpha ×100= 400. Total =400+400=800rad

θ = 5 rev, α = 2 rev/s2, ω0 = 0 ; ω = ? ω2 = (2 α θ) ω = √(2 x 2x 5) = 2 √5 rev/s. or θ = 10π rad,  α= 4π rad/s2, ω0 =...

A wheel rotating at a speed of 600 rpm. ω0 = 600 rpm = 10 revolutions per second. T = 10 sec. (In 10 sec. it comes to rest) ω = 0 Therefore ω0 = –αt α...

(c) They will be together at the starting point after the L.C.M of 36, 48 and 42 L.C.M. of 36, 48, 42 = 1008 seconds

The correct answer is all  (a) kinetic  (b) total  (c) mechanical  (d) internal.