A wheel rotating at a speed of 600 rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds.

The distance travelled in first 8 s, x1= 0 + 1 /2 (5) (8) 2 = 160 m.  At this point the velocity v = u+ at = 0 + (5×8)...

ω0 = 0 ; ρ = 100 rev/s ; ω = 2 ; ρ = 200 π rad/s ω = ω0 = αt ω = αt α= (200 π)/4 = 50 π rad /s2 or 25 rev/s2 θ = ω0t + 1/2...

θ = 100 π; t = 5 sec θ = 1/2 αt2 = 100 π = 1/2 α 25 α = 8π × 5 = 40 π rad/s = 20 rev/s α = 8π rad/s2 = 4 rev/s2 ω = 40π rad/s2...

Theta=wt+1/2alpha Tsq. By this we will get Theta=200. For first 10 and last 10 sec theta will be same therefore =400. And for 10 sec of middle is alpha ×100= 400. Total =400+400=800rad

A disc of radius = 10 cm = 0.1 m Angular velocity = 20 rad/s Linear velocity on the rim = ωr = 20 × 0.1 = 2 m/s Linear velocity at the...

(c) They will be together at the starting point after the L.C.M of 36, 48 and 42 L.C.M. of 36, 48, 42 = 1008 seconds

 The correct answer is: (a), (c) (a), kinetic  (c) mechanical

The correct answer is all  (a) kinetic  (b) total  (c) mechanical  (d) internal.

emf = dϕ/dt = dB.Acosθ/dt = BAsinθω = –BAωsinθ (dq/dt = the rate of change of angle between arc vector and B = ω) (a) emf maximum = BAω = 0.010 × 25 × 10–4 ×...