A disc of radius 10 cm is rotating about its axis at an angular speed of 20 rad/s. Find the linear speed of
(a) a point on the rim,
(b) the middle point of a radius.
A disc of radius = 10 cm = 0.1 m
Angular velocity = 20 rad/s
Linear velocity on the rim = ωr = 20 × 0.1 = 2 m/s
Linear velocity at the middle of radius = ωr/2 = 20 × (0.1)/2 = 1 m/s.
No
No
Yes
No
No
Yes
Angular momentum and total energy at all points of the orbit of a comet moving in a highly elliptical orbit around the Sun are constant. Its linear speed, angular speed,...
(c) IA <IB
Explanation:
Let the density of iron plate be ρ.
Mass of first disc m = πr²tρ
M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ
Mass of second disc = M =...
The correct answer is (b)
Explanation:
Moment of inertia of the ring I = Mr²
Angular Momentum = I⍵
When the masses are attached, the moment of Inertia I'= Mr²+2mr²
=(M+2m)r²
Let the new angular speed...
(c) remains unchanged
Explanation:
If there is no external torque, the angular momentum is conserved. It is true if the moment of inertia of the rotating part of the stool is negligible...
The Block is moving the rim of the pulley
The pulley is moving at a ω = 10 rad/s
Therefore the radius of the pulley = 20 cm
Therefore linear velocity on the...
Initial angular velocity = 20 rad/s
Therefore α = 2 rad/s2
t1 = ω/α 1 = 20/2 = 10 sec
Therefore 10 sec it will come to rest.
Since the same torque continues to act...
