A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4R is made from an iron plate of thickness t/4.

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Solution: Given diameter of copper rod, d = 1 cm Hence its radius, R= (1/2) cm Height of rod, H = length of rod = 8 cm ∴ Volume of rod = πR2H cubic units =...

Thickness of one book = 20 mm  Thickness of 5 books = 20 x 5 = 100 mm  Thickness of one paper = 0.016 mm  Thickness of 5 papers = 0.016 x 5...

(c) IA <IB   Explanation:  Let the density of iron plate be ρ.  Mass of first disc m = πr²tρ  M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ  Mass of second disc = M =...

The correct answer is (c) 24 s

(d) The radius of the diffraction disc will be >0.1mm.

(c) IA <IB   Explanation:  Let the density of iron plate be ρ.  Mass of first disc m = πr²tρ  M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ  Mass of second disc = M = π(4r)²(t/4)ρ =...

(c) The loss of heat is directly proportional to the surface area, hence loss of heat will be earlier in case of sphere because it has the maximum surface area.

Dynamic Plate Resistance rp = 10KΩ = 104Ω δIp = ? δVp = 220 – 220 = 20V δIp = (δVp/rp)/ Vg = constant. = 20/104 = 0.002A = 2mA