A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of length 18 m of uniform thickness. Find the thickness of the wire.


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Solution:

Given diameter of copper rod, d = 1 cm
Hence its radius, R= (1/2) cm
Height of rod, H = length of rod = 8 cm
∴ Volume of rod = πR2H cubic units
= π x (1/2)2 x 8 cubic cm
= 2π cubic cm
Given that cylindrical rod is drawn into a cylindrical wire of length, h = 18 m
That is, h = 1800 cm
∴ Volume of cylindrical rod = Volume of cylindrical wire
Let r be the radius of the wire
Hence 2π = πr2h
That is, 2 = r2 x 1800
r2 = (1/900)
Therefore, r = (1/30) cm = 1/3 mm
Diameter or thickness = 2(1/3) = (2/3) mm

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Note the volume of the material in both the shapes will be the same only.
Volume of rod1=volume of rod2
`pi(r_1)^2h_1=pi(r_2)^2h_2`
substituting values we get,
`1/2 xx1/2xx8=1800xxr_2^2`
=>`(r_2)=1/30 cm` thickness of wire=`2/30 cm`

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