A steel wire and a copper wire of equal length and equal cross-sectional area are joined end to end and the combination is subjected to a tension.

Solution: Given diameter of copper rod, d = 1 cm Hence its radius, R= (1/2) cm Height of rod, H = length of rod = 8 cm ∴ Volume of rod = πR2H cubic units =...

you are mistaken in that centripetal force is provided by the resultant force of tension(T) in the wire and the weight(mg) of the particle in vertical circle.Equation at the lowest...

(c) (l1T2-l2 T1)/(T2-T1) Explanation:  If the original length of the wire be l and the area of the cross-section a, then   l₁-l = T₁*l/Ya  And l₂-l = T₂*l/Ya  Dividing we get,  (l₁ -l)*T₂ = (l₂-l)*T₁  →l₁T₂ -lT₂= l₂...

Length of wire  L= 3 m,  Load F = 10*10 N =100 N, {taking g = 10 m/s²}  Area of cross-section A = 4 mm²  →A = 4x10⁻⁶ m²  (a) The stress = Load...

Length of the rod =L =2 m  The length increased during the night = l =0.1 cm= 0.001 m  The strain developed during the night =l/L =0.001/2 =0.0005  If the tension developed =...

Cross-sectional area A =0.01 cm²   →A = 0.01/10000 =1x10⁻⁶ m²  Stress = 20/1x10⁻⁶ N/m² =2x10⁷ N/m²  Hence the longitudinal strain =Stress/Y =2x10⁷/1.1x10¹¹  =1.82x10⁻⁴  Poisson's ratio = 0.32  Lateral strain = 0.32*1.82x10⁻⁴ =5.82x10⁻⁵  Taking the cross-section as...

The correct answer is (c) 2C and V

(a) equal amounts of thermal energy must be produced in the resistors (b) unequal amounts of thermal energy may be produced

Magnetic field inside the solenoid B =μ0nI n → number of turns per unit length, I → current flowing, ϕ' = Magnetic field through each turn = BA = μ0nIA Total magnetic flux linked...

K = 45w/m-°C ℓ = 60cm = 60 × 10–2m A = 0.2cm2 = 0.2 × 10–4m2 Rate of heat flow, = KA( θ1 + θ2 )/l = (45 x 0.2 x 10-4 x...