A steel frame (K = 45W/m-°C) of total length 60cm and - cross-sectional area 0.20cm2, forms three sides of a square. The free ends are maintained at 20°C and 40°C. Find the rate of heat flow through a cross-section of the frame.


Share with your friends
Call

K = 45w/m-°C
ℓ = 60cm = 60 × 10–2m
A = 0.2cm2 = 0.2 × 10–4m2
Rate of heat flow,
= KA( θ1 + θ2 )/l = (45 x 0.2 x 10-4 x 20)/(60 x 10-2) = 30 x 10-3  = 0.03w