A copper wire of cross-sectional area 0.01 cm^2 is under a tension of 20 N. Find the decrease in the cross-sectional area.

Solution: Given that,Tension in string, T = 40N , mass of string, m = 5gm = 0.005 kg ,length of the string, l = 10 m ,  v = ? We know that...

(c) (l1T2-l2 T1)/(T2-T1) Explanation:  If the original length of the wire be l and the area of the cross-section a, then   l₁-l = T₁*l/Ya  And l₂-l = T₂*l/Ya  Dividing we get,  (l₁ -l)*T₂ = (l₂-l)*T₁  →l₁T₂ -lT₂= l₂...

(b) : The stability of the carbonates of the alkaline earth metals increases on moving down the group. The solubility of carbonate of metals in water is generally low. However...

l = 2m, f0 = 100 Hz, T = 160 N f0 = 1/ 2l √(T /m) =>m = 1 g/m. So, the linear mass density is 1 g/m.

Length of wire  L= 3 m,  Load F = 10*10 N =100 N, {taking g = 10 m/s²}  Area of cross-section A = 4 mm²  →A = 4x10⁻⁶ m²  (a) The stress = Load...

(a) Since both types of wires are joined end to end, the same load will be on the cross-sections of them. If the load = F and the area of...

Length of the rod =L =2 m  The length increased during the night = l =0.1 cm= 0.001 m  The strain developed during the night =l/L =0.001/2 =0.0005  If the tension developed =...

Magnetic field inside the solenoid B =μ0nI n → number of turns per unit length, I → current flowing, ϕ' = Magnetic field through each turn = BA = μ0nIA Total magnetic flux linked...

K = 45w/m-°C ℓ = 60cm = 60 × 10–2m A = 0.2cm2 = 0.2 × 10–4m2 Rate of heat flow, = KA( θ1 + θ2 )/l = (45 x 0.2 x 10-4 x...

b. hydration energies of cations