Visible light passing through a circular hole forms a diffraction disc of radius 0.1mm on a screen. If X-ray is passed through the same set-up, the radius of the diffraction disc will be
(c) 2mv2/r must be acting on the system
Explanation:
Since the heavy ring and the small particle have equal masses, the center of mass of the system will be at r/2 from the...
(c) IA <IB
Explanation:
Let the density of iron plate be ρ.
Mass of first disc m = πr²tρ
M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ
Mass of second disc = M =...
(c) IA <IB
Explanation:
Let the density of iron plate be ρ.
Mass of first disc m = πr²tρ
M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ
Mass of second disc = M = π(4r)²(t/4)ρ =...
The waves diffracted at the edge of circular obstacle produce constructive interference at the centre of the shadow; producing a bright spot.
Difference between Interference and Diffraction
Interference
Diffraction
1.
All bright fringes are of...