A wheel rotating with uniform angular acceleration covers 50 revolutions in the first five seconds after the start.

Here we have,  Acceleration, a = 4 m/s2  Initial velocity, u = 0 m/s  Time, t = 10 s  Distance covered (s) =?  We know that, s = ut + 1 /2 at2  ⇒ s =...

(i) A body is said in uniform acceleration when its motion is along a straight line and its velocity changes by equal magnitude in equal interval of time.  (ii) A body...

The right answer is (b) mω02a Explanation:  The frame of reference is rotating with a uniform angular speed ω0, so it has an acceleration towards the center and it is a non-inertial...

ω0 = 0 ; ρ = 100 rev/s ; ω = 2 ; ρ = 200 π rad/s ω = ω0 = αt ω = αt α= (200 π)/4 = 50 π rad /s2 or 25 rev/s2 θ = ω0t + 1/2...

Theta=wt+1/2alpha Tsq. By this we will get Theta=200. For first 10 and last 10 sec theta will be same therefore =400. And for 10 sec of middle is alpha ×100= 400. Total =400+400=800rad

θ = 5 rev, α = 2 rev/s2, ω0 = 0 ; ω = ? ω2 = (2 α θ) ω = √(2 x 2x 5) = 2 √5 rev/s. or θ = 10π rad,  α= 4π rad/s2, ω0 =...

A wheel rotating at a speed of 600 rpm. ω0 = 600 rpm = 10 revolutions per second. T = 10 sec. (In 10 sec. it comes to rest) ω = 0 Therefore ω0 = –αt α...

(c) They will be together at the starting point after the L.C.M of 36, 48 and 42 L.C.M. of 36, 48, 42 = 1008 seconds

(B) Uniform motion