A wheel starting from rest is uniformly accelerated at 4 rad/s 2 for 10 seconds.It is allowed to rotate uniformly for the next 10 seconds

(a) on the rear wheels is in the forward direction (b) on the front wheels is in the backward direction (c) on the rear wheels has a larger magnitude than the Explanation:  When accelerating the torque...

ω0 = 0 ; ρ = 100 rev/s ; ω = 2 ; ρ = 200 π rad/s ω = ω0 = αt ω = αt α= (200 π)/4 = 50 π rad /s2 or 25 rev/s2 θ = ω0t + 1/2...

θ = 100 π; t = 5 sec θ = 1/2 αt2 = 100 π = 1/2 α 25 α = 8π × 5 = 40 π rad/s = 20 rev/s α = 8π rad/s2 = 4 rev/s2 ω = 40π rad/s2...

Theta=wt+1/2alpha Tsq. By this we will get Theta=200. For first 10 and last 10 sec theta will be same therefore =400. And for 10 sec of middle is alpha ×100= 400. Total =400+400=800rad

A wheel rotating at a speed of 600 rpm. ω0 = 600 rpm = 10 revolutions per second. T = 10 sec. (In 10 sec. it comes to rest) ω = 0 Therefore ω0 = –αt α...

Initial angular velocity = 20 rad/s Therefore α = 2 rad/s2  t1 = ω/α 1 = 20/2 = 10 sec Therefore 10 sec it will come to rest. Since the same torque continues to act...

(c) They will be together at the starting point after the L.C.M of 36, 48 and 42 L.C.M. of 36, 48, 42 = 1008 seconds

 The correct answer is: (a), (c) (a), kinetic  (c) mechanical

The correct answer is all  (a) kinetic  (b) total  (c) mechanical  (d) internal.

(a) on the rear wheels is in the forward direction (b) on the front wheels is in the backward direction (c) on the rear wheels has a larger magnitude than the Explanation:  When accelerating the...