A spinning wheel A is brought in contact with another wheel E initially at rest.

Initial difference in height = (150 – 100) m = 50 m  Distance travelled by first body in 2 s = h1 = 0 + 1/ 2 g (2)2 = 2...

The correct answer is (a) vA > vB   Explanation:  Let T be the torque and A and A' be the angular accelerations. A = T/IA and A' = T/IB. Clearly A >A'. In...

ω0 = 0 ; ρ = 100 rev/s ; ω = 2 ; ρ = 200 π rad/s ω = ω0 = αt ω = αt α= (200 π)/4 = 50 π rad /s2 or 25 rev/s2 θ = ω0t + 1/2...

Theta=wt+1/2alpha Tsq. By this we will get Theta=200. For first 10 and last 10 sec theta will be same therefore =400. And for 10 sec of middle is alpha ×100= 400. Total =400+400=800rad

A wheel rotating at a speed of 600 rpm. ω0 = 600 rpm = 10 revolutions per second. T = 10 sec. (In 10 sec. it comes to rest) ω = 0 Therefore ω0 = –αt α...

 The correct answer is: (a), (c) (a), kinetic  (c) mechanical

(c) Both A and B are true

The correct answer is (a) vA > vB   Explanation:  Let T be the torque and A and A' be the angular accelerations. A = T/IA and A' = T/IB. Clearly A >A'. In fact, the...

(c) Ball bearings are used to reduce friction and friction is directly propertional to effective surface area. So if effective surface area is reduced then friction will also reduce.

(C) The speed of the ship is 0.1m/s. Explanation: acceleration of ship a=5*104 N/ 3*107 KG                                  =5/3...