Find the angular velocity of a body rotating with an acceleration of 2 rev/s ^2 as it completes the 5th revolution after the start.

Here we have,  Initial velocity, u = 0 m/s  Acceleration (a) = 2 cm/s2 = 0.02 m/s2  Time (t) = 3 s  Final velocity, v = ?  We know that, v = u + at  Therefore,...

Here we have,  Acceleration, a = 4 m/s2  Initial velocity, u = 0 m/s  Time, t = 10 s  Distance covered (s) =?  We know that, s = ut + 1 /2 at2  ⇒ s =...

Using the equation of motion                                                     ...

(d) g downward Explanation: Gravity is the only force acting on the stone when it is released. And, we know that gravity is always in the downward direction.

(c) is perpendicular to the acceleration for one instant only Explanation: In projectile motion, velocity is perpendicular to acceleration only at the highest point. Here, velocity is along the horizontal direction and...

(c) horizontal and intersecting the axis Explanation:  Since the body is rotating uniformly, a particle not on the axis moves in a uniform circular motion. This circle will be horizontal with its center at...

ω0 = 0 ; ρ = 100 rev/s ; ω = 2 ; ρ = 200 π rad/s ω = ω0 = αt ω = αt α= (200 π)/4 = 50 π rad /s2 or 25 rev/s2 θ = ω0t + 1/2...

θ = 100 π; t = 5 sec θ = 1/2 αt2 = 100 π = 1/2 α 25 α = 8π × 5 = 40 π rad/s = 20 rev/s α = 8π rad/s2 = 4 rev/s2 ω = 40π rad/s2...

α= 1 rad/s2, ω0 = 5 rad/s; ω = 15 rad/s w = w0 + αt  t = (ω – ω0)/α = (15 – 5)/1 = 10 sec Also, θ = ω0t + 1/2 αt2 = 5 ×10...

A disc of radius = 10 cm = 0.1 m Angular velocity = 20 rad/s Linear velocity on the rim = ωr = 20 × 0.1 = 2 m/s Linear velocity at the...