A body rotates about a fixed axis with an angular acceleration of one radian/second/second. Through what angle does it rotate during the time in which its angular velocity increases from 5 rad/s to 15 rad/s.
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Internal fertilization occurs Option A: in female body. Option B: outside female body. Option C: in male body. Option D: outside male body.
Correct Option: A Internal fertilization occurs inside female body
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A particle of mass m rotates with a uniform angular speed ω. It is viewed from a frame rotating about the
The right answer is (b) mω02a Explanation: The frame of reference is rotating with a uniform angular speed ω0, so it has an acceleration towards the center and it is a non-inertial...
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A body is uniformly rotating about an axis fixed in an inertial frame of reference. Let A be a unit vector along the axis of rotation
(c) 0 Explanation: Since the body is uniformly rotating, the resultant force on the particle P will be in the radial direction. So again the directions of A and B will be...
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A body is rotating uniformly about a vertical axis fixed in an inertial frame. The resultant force on a particle of the body not on the axis is
(c) horizontal and intersecting the axis Explanation: Since the body is rotating uniformly, a particle not on the axis moves in a uniform circular motion. This circle will be horizontal with its center at...
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A wheel is making revolutions about its axis with uniform angular acceleration. Starting from rest, it reaches 100 rev/sec in 4 seconds.
ω0 = 0 ; ρ = 100 rev/s ; ω = 2 ; ρ = 200 π rad/s ω = ω0 = αt ω = αt α= (200 π)/4 = 50 π rad /s2 or 25 rev/s2 θ = ω0t + 1/2...
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Find the angular velocity of a body rotating with an acceleration of 2 rev/s ^2 as it completes the 5th revolution after the start.
θ = 5 rev, α = 2 rev/s2, ω0 = 0 ; ω = ? ω2 = (2 α θ) ω = √(2 x 2x 5) = 2 √5 rev/s. or θ = 10π rad, α= 4π rad/s2, ω0 =...
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A disc rotates about its axis with a constant angular acceleration of 4 rad/s^2. Find the radial and tangential accelerations of a particle at a
t = 1 sec, r = 1 cm = 0.01 m = 4 rd/s2 Therefore ω= αt = 4 rad/s Therefore radial acceleration, An =ω2r = 0.16 m/s2 = 16 cm/s2
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A diver having a moment of inertia of 6.0 kg-m^2 about an axis through its centre of mass rotates at an angular speed
I1 = 6 kg-m2, ω1 = 2 rad/s , I2 = 5 kg-m2 Since external torque = 0 Therefore I1ω1 = I2ω2 ω2 = (6 × 2) / 5 = 2.4 rad/s
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A rod of length I rotates with a small but uniform angular velocity co about its perpendicular bisector.
The correct answer is (b) 1/8(ωBl2).
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A rod of length I rotates with a uniform angular velocity co about its perpendicular bisector.
The correct answer is (a) zero.
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