A diver having a moment of inertia of 6.0 kg-m2 about an axis through its centre of mass rotates at an angular speed of 2 rad/s about this axis. If he folds his hands and feet to decrease the moment of inertia to 5.0 kg-m2, what will be the new angular speed ?


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I1 = 6 kg-m2, ω1 = 2 rad/s , I2 = 5 kg-m2
Since external torque = 0
Therefore I1ω​1 = I2ω​2
ω2 = (6 × 2) / 5 = 2.4 rad/s

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