The moment of inertia of a uniform semicircular wire of mass M and radius r about a line perpendicular to the plane of the wire through the centre is

Inclination angle (∅)= 30°  Speed of centre of mass (v)= 5m/s  (A) acceleration of the cylinder rolling up the inclined plane is  Given by the formula,  a = -gsin∅/(1 + k²/r²)  Where K = radius...

Let AB be the line joining the points, (1, −1, 2) and (3, 4, − 2), and CD be the line joining the points, (0, 3, 2) and (3, 5,...

Geometric centre; No The centre of mass (C.M.) is a point where the mass of a body is supposed to be concentrated. For the given geometric shapes having a uniform mass density,...

(a) v = (v1 + v2)/2. Explanation:  Let t be the time related to each velocity. Total distance travelled =v1t+v2t. Total time taken=2t. Hence average velocity = v1t+v2t/2t  =(v1+v2)/2.

(a) : A circular wire behaves like a ring M.I. about its diameter = (MR2)/2.

The correct answer is (4) w = GMm / R = 6.67 × 10-10 J

I1 = 6 kg-m2, ω1 = 2 rad/s , I2 = 5 kg-m2 Since external torque = 0 Therefore I1ω​1 = I2ω​2 ω2 = (6 × 2) / 5 = 2.4 rad/s

(c) The kinetic energy

The correct answer is (c) (d) (c) it is rotated about a diameter (d) it is deformed.

The length of the wire is πR+R right ? So according to the formula for force, the force should be BI(πR+R )?