Moment of inertia of a circular wire of mass M and radius R about its diameter is

Solution: Given diameter of copper rod, d = 1 cm Hence its radius, R= (1/2) cm Height of rod, H = length of rod = 8 cm ∴ Volume of rod = πR2H cubic units =...

Here, inner radius (r) = 24/ 2 cm = 12 cm  Outer radius (R) = 28/ 2 cm = 14 cm, h = 35 cm  Volume of the wood used in the...

(b) The magnitude of the frictional force on the car is greater than mv2/r  (c) The friction coefficient between the ground and the car is not less than α/g.  Explanation:  Since the circular...

(c) IA <IB   Explanation:  Let the density of iron plate be ρ.  Mass of first disc m = πr²tρ  M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ  Mass of second disc = M =...

(a) Mr2   Explanation:  Since the mass of the wire is at a distance r away from the axis. Hence the option (a).

The correct answer is (b) Explanation:  Moment of inertia of the ring I = Mr²  Angular Momentum = I⍵  When the masses are attached, the moment of Inertia I'= Mr²+2mr²  =(M+2m)r²  Let the new angular speed...

The correct answer is (a) 1/8 Explanation:  For wires of the same material, the elongation is directly proportional to the length and inversely proportional to the cross-sectional area.  Δl/l = F/AY  →Δl =Fl/AY {Here...

I1 = 6 kg-m2, ω1 = 2 rad/s , I2 = 5 kg-m2 Since external torque = 0 Therefore I1ω​1 = I2ω​2 ω2 = (6 × 2) / 5 = 2.4 rad/s

d1 = 2 cm = 2 × 10–2 t1 = 0°C, t2 = 100°C αal = 2.3 × 10–5 /°C d2 = d1 (1 +αΔt) = 2 × 10–2 (1 + 2.3 ×...

emf = dϕ/dt = dB.Acosθ/dt = BAsinθω = –BAωsinθ (dq/dt = the rate of change of angle between arc vector and B = ω) (a) emf maximum = BAω = 0.010 × 25 × 10–4 ×...