A semicircular wire of radius 5.0cm carries a current of 5.0A.

(a) Mr2   Explanation:  Since the mass of the wire is at a distance r away from the axis. Hence the option (a).

The correct answer is (c) upwards

(b) the directions of the magnetic fields are the same (c) the magnitudes of the magnetic fields are equal (d) the field at one point is opposite to that at the other...

(b) minimum at the axis of the wire (c) maximum at the surface of the wire

(c) remain almost constant

I = 2 m, R = 5Ω, i = 10 A, E = ? V = iR = 10 x 5 = 50 V E=V/I=50/2=25 V/m.

n = 50, r = 0.02m A = π × (0.02)2, B = 0.02T i = 5A, μ = niA = 50 × 5 × π × 4 × 10–4 τ is max. when θ = 90° τ = μ × B = μBSin90° = μB...

n = 500, r = 0.02m, θ = 30° i = 1A, B = 4 × 10–1T i = μ × B = μB Sin30° = niABSin30° = 500 × 1 × 3.14 × 4 × 10–4 ×...

emf = dϕ/dt = dB.Acosθ/dt = BAsinθω = –BAωsinθ (dq/dt = the rate of change of angle between arc vector and B = ω) (a) emf maximum = BAω = 0.010 × 25 × 10–4 ×...

It is true that measure of price elasticity of demand for a normal good carrier minus sign because there is an inverse relationship between P and Q. Whereas there is...