A stone is released from an elevator going up with an acceleration a. The acceleration of the stone after the release is
(a) a upward
(b) (g — a) upward
(c) (g— a) downward
(d) g downward.
According to the equation of motion under gravity v2 − u2 = 2gs
Where,
u = Initial velocity of the stone = 0 m/s
v = Final velocity of the stone
s = Height...
Here we have,
Initial velocity, u = 0 m/s
Acceleration (a) = 2 cm/s2 = 0.02 m/s2
Time (t) = 3 s
Final velocity, v = ?
We know that, v = u + at
Therefore,...
(a) If the velocity and acceleration have opposite sign, the object is slowing down.
(b) If the position and velocity have opposite sign, the particle is moving towards the origin.
(d) If...
The correct answer is(c) < 76 cm
EXPLANATION:
The pressure of the atmosphere remains the same in both the conditions =ρg*(0.76). But in the upward accelerating elevator the pressure of the mercury...
The correct answer is (c) > 76 cm
EXPLANATION:
Since the pressure of the mercury column 76 cm high in the upward accelerating elevator is more than the stationary elevator condition due...
The correct answer is (d) 20 cm.
Explanation:
The rise in a capillary tube is given as h = 2S.cosθ/rρg When the entire arrangement is in a freely falling elevator, the effective...
(b) going up and speeding up
(c) going down and slowing down
Explanation:
If we are going to use Newton's laws of motion in a non-inertial frame like accelerating elevator, we have to...