A bus starting from rest moves with a uniform acceleration of 0.1ms –2 for 2 minutes. Find
(a) the speed acquired,
(b) the distance travelled.
Acceleration (a)=0.1ms-2 Time (t)=120seconds W k t, a) distance S = ut+1/2 a t2 = 0+1/2 x 0.1 x 14400 = 720 m b) speed = distance/ time = 720 / 120 = 6 ms-1 In this solved problem...
1 Answers 1 views(i) A body is said in uniform acceleration when its motion is along a straight line and its velocity changes by equal magnitude in equal interval of time. (ii) A body...
1 Answers 1 views(ii) 25 km------------------- Solution: Case I: Speed = 40 km/h Time = 15 min = 15/60 hour Distance = Speed × Time = 40×15/60=10 km Case II: Speed = 60 km/h Time = 15 min = 15/60 hour Distance...
1 Answers 1 viewsAnswer is (b) 10 m/s
1 Answers 2 views(d) > 500N for time Δt1 and Δt3 and 500N for Δt2. Explanation: During the constant velocity for time Δt2 there is no relative movement between the man and the seat and only force applied by the seat on...
1 Answers 1 viewsω0 = 0 ; ρ = 100 rev/s ; ω = 2 ; ρ = 200 π rad/s ω = ω0 = αt ω = αt α= (200 π)/4 = 50 π rad /s2 or 25 rev/s2 θ = ω0t + 1/2...
1 Answers 1 views(d) > 500N for time Δt1 and Δt3 and 500N for Δt2. Explanation: During the constant velocity for time Δt2 there is no relative movement between the man and the seat and only force applied by the...
1 Answers 1 views(d) its velocity and acceleration both change. Explanation: Velocity and acceleration are both vectors and a vectors is fully defined with its magnitude and direction. Even when one entity changes, the vector...
1 Answers 1 views(c) Speed of bus = Distance covered / Time taken =2924/43= 68 kmph.
1 Answers 1 views(a) Distance covered = Speed × Time = 49 × 7 = 343km
1 Answers 1 views