A bus starting from rest moves with a uniform acceleration of 0.1ms –2 for 2 minutes. Find 

(a) the speed acquired, 

(b) the distance travelled.


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Acceleration (a)=0.1ms-2
Time (t)=120seconds
W k t,
a) distance
       S = ut+1/2 a t2
          = 0+1/2 x 0.1 x 14400 = 720 m
b) speed = distance/ time
                  = 720 / 120
                  = 6 ms-1
 In this solved problem the speed is wright or wrong.... If it is wrong means how??  
     Here I am confused...

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Answer 1: 

Here we have, 

Initial velocity (u) = 0 m/s 

Acceleration (a) = 0.1ms–2 

Time (t) = 2 minute = 120 seconds 

(a) The speed acquired: 

We know that, v = u + at 

⇒ v = 0 + 0.1 × 120 m/s 

⇒ v = 12 m/s

Thus, the bus will acquire a speed of 12 m/s after 2 minute with the given acceleration.

(b) The distance travelled: 

We know that, s = ut + 1/ 2 at2 

= 0 × 120 + 1 /2 × 0.1 × (120)2 

= 1/ 2 × 0.1 ×14400 m = 720 m 

Thus, bus will travel a distance of 720 m in the given time of 2 minute. 

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