A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:

Acceleration (a)=0.1ms-2 Time (t)=120seconds W k t, a) distance        S = ut+1/2 a t2           = 0+1/2 x 0.1 x 14400 = 720 m b) speed = distance/ time                   = 720 / 120                   = 6 ms-1  In this solved problem...

(c) rectilinear and periodic both. 

(c) vA = vB = vc. (d) vB =1/2 (vA+vc).

(c)  2/v = 1/v1 + 1/v2. Explanation: Time taken during first phase =  x/v1 and during second phase =  x/v2.  Total distance =2x   Total time taken = (x/v1)+(x/v2) = x(1/v1 +1/v2)     Average velocity =Total distance/Total...

 (c) Time taken to cover first 75 km of distance =75/25 =3 hours Time taken to cover next 25 km of distance =25/5 =5 hours Time taken to cover last 50 km of its journey =50/25...

(e) Speed of the car = Distance Covered / TimeTaken = 816/12 =68 kmph.

(a) Distance covered = Speed × Time = 49 × 7 = 343km

(e) Time taken to cover a distance of 45 kms =45/15 = 3 hours Time taken to cover a distance of 50 kms =50/25 = 2 hours Time taken to cover distance of 25...

(c) Period between 1990-92 was second plan holiday. The first plan holiday was between 1966-69.