Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is released by fission of each atom of `.^(235)U`. (Avogardo constant is `= 6.023 xx 10^(26) kg mol^(-1)`)
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The value of `((100),(0))((200),(150))+((100),(1))((200),(151))+......+((100),(50))((200),(200))` equals (where `((n),(r ))="^(n)C_(r)`)
Correct Answer - A `(a)` Writing `((200),(r ))=((200),(200-r))`, we have `((100),(0))((200),(50))+((100),(1))((200),(49))+((100),(2))((200),(48))+......+((100),(50))((200),(0))` `=` Coefficient of `x^(50)` in the expansion of `(1+x)^(100)(x+1)^(200)` `=` Coefficient of `x^(50)` in the binomial expansion of `(1+x)^(300)` `=((300),(50))`
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When `._(92)U^(235)` undergoes fission, 0.1% of the original mass is released into energy. How much energy is released by an atom bomb which contains
Correct Answer - `9 xx 10^(14)` J
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When an atom of `._(92)U^(235)` undergo fission, about 200 MeV energy is released Suppose that a reactor using `._(92)U^(235)` has an output of 700 MW
Correct Answer - `9.5 xx 10^(24), 3.7` kg
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The `._(92)^(235)U` absorbs a slow neutron (thermal neutron) & undergoes a fission represented by (i) The energy release E per fission. (ii) The energ
Correct Answer - [(i) 200.68 MeV` (ii) `22.86 MWh`]
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Calculate the energy released by `1 g` of natural uranium assuming `200 MeV` is released in eaech fission event and that the fissionable isotope `U^23
Correct Answer - `[5.7 xx 10^(8) J]`
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Assuming 1 metric ton of coal gives heat of combustion equal to 8 kcal and a single fission of `.^(235)U` releases 200 MeV. Calculate the minimum cons
Correct Answer - `[M = 4.077 xx 10^(-8) kg]`
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sion giving 0.1 % of its original mass released as energy. (a) How much energy is released by an atomic bomb that contains `10 kg` of `.^(235)U`. (b)
Correct Answer - `[9 xx 10^(14), 2.25 xx 10^(5) "ton"]`
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Assuming the splitting of `U^235` nucleus liberates `200 MeV` energy, find (a) the energy liberated in the fission of 1 kg of `U^235` and (b) the mass
Correct Answer - [(a) `8.2 xx 10^(10)kJ, 2.7 xx 10^(6) kg` (b) `1.5 g`]
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A uranium nucleus `.^(235)U` liberates 200 MeV per fission 1.5 kg of uranium reacts during explosion of a uranium bomb. What is the mass of an equival
Correct Answer - `3 xx 10^(7) kg`
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Calculate the energy in Mev released in the nuclear reaction :
Given : mIr = 173.97 u mRe = 169.96 u mHe = 4.0026 u To find : Energy released Formulae : i. Δm = (mass of 174Ir) – (mass of 170Re + mass of 4He) ii. E =...
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