Calculate the energy released by `1 g` of natural uranium assuming `200 MeV` is released in eaech fission event and that the fissionable isotope `U^235` has an abundance of 0.7% by weight in natural uranium.
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The probability of event `A` is `3//4`. The probability of event `B`, given that event `A` occurs is `1//4`. The probability of event `A`, given that
Correct Answer - C `(c )` `P(A)=(3)/(4)`, `P(B//A)=(1)/(4)` `P(A//B)=(2)/(3)` `P(B//A)=(P(BnnA))/(P(A))=(1)/(4)` (given) `:.P(BnnA)=(3)/(4)*(1)/(4)=(3)/(16)` Now `P(A//B)=(P(AnnB))/(P(B))=(2)/(3)`(given) `:.P(B)=(3)/(2)*(3)/(16)=(9)/(32)` `:. P(AuuB)=(3)/(4)+(9)/(32)-(3)/(16)=(24+9-6)/(32)=(27)/(32)` `:. P(A^(C )nnB^(C ))=1-P(AuuB)=1-(27)/(32)=(5)/(32)`
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Calculate the binding energy in MeV of Uranium 238 from the following data Mass of `.^(1)H_(1) = 1.008142 am u`, Mass of `._(0)n^(1) = 1.008982 am u`
Correct Answer - 7.5714 MeV, `13.49 xx 10^(-30) kg`
2 Answers 4 views
When `._(92)U^(235)` undergoes fission, 0.1% of the original mass is released into energy. How much energy is released by an atom bomb which contains
Correct Answer - `9 xx 10^(14)` J
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When an atom of `._(92)U^(235)` undergo fission, about 200 MeV energy is released Suppose that a reactor using `._(92)U^(235)` has an output of 700 MW
Correct Answer - `9.5 xx 10^(24), 3.7` kg
2 Answers 1 views
Assuming 1 metric ton of coal gives heat of combustion equal to 8 kcal and a single fission of `.^(235)U` releases 200 MeV. Calculate the minimum cons
Correct Answer - `[M = 4.077 xx 10^(-8) kg]`
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Assuming the splitting of `U^235` nucleus liberates `200 MeV` energy, find (a) the energy liberated in the fission of 1 kg of `U^235` and (b) the mass
Correct Answer - [(a) `8.2 xx 10^(10)kJ, 2.7 xx 10^(6) kg` (b) `1.5 g`]
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Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is released by fission of each atom of `.^(235)
Correct Answer - `5.1 xx 10^(23) MeV`
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A uranium nucleus `.^(235)U` liberates 200 MeV per fission 1.5 kg of uranium reacts during explosion of a uranium bomb. What is the mass of an equival
Correct Answer - `3 xx 10^(7) kg`
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Fill in the blacks: (i) The probability of an impossible event is ………. . (ii) The probability of a sure event is …….. . (iii) For any event E, P(E ) +
Correct Answer - (i) 0 (ii)1(iii)1(iv) 0,1 (v) 1
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Fill in the blanks . (i) Probability of an impossible event= …….. (ii) Probability of a sure event = …… (iii) Let E be the event . Then , P(not E) = …
Correct Answer - (i) 0 (ii) 1 (iii) 1-P(E) (iv) 1 (v) 0, 1
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