Assuming the splitting of `U^235` nucleus liberates `200 MeV` energy, find
(a) the energy liberated in the fission of 1 kg of `U^235` and
(b) the mass of the coal with calorific value of `30 kJ//g` which is equivalent to `1 kg` of `U^235`.


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Correct Answer - [(a) `8.2 xx 10^(10)kJ, 2.7 xx 10^(6) kg` (b) `1.5 g`]

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