Assuming the splitting of `U^235` nucleus liberates `200 MeV` energy, find (a) the energy liberated in the fission of 1 kg of `U^235` and (b) the mass of the coal with calorific value of `30 kJ//g` which is equivalent to `1 kg` of `U^235`.
Answered Feb 05, 2023
Correct Answer - [(a) `8.2 xx 10^(10)kJ, 2.7 xx 10^(6) kg` (b) `1.5 g`]
Correct Answer - 1.09 V
Correct Answer - `198.77` MeV
Correct Answer - `9 xx 10^(14)` J
Correct Answer - `9.5 xx 10^(24), 3.7` kg
Correct Answer - [(i) 200.68 MeV` (ii) `22.86 MWh`]
Correct Answer - `[5.7 xx 10^(8) J]`
Correct Answer - `[M = 4.077 xx 10^(-8) kg]`
Correct Answer - `[3.4 xx 10^(5) m//s, 0.020]`
Correct Answer - `5.1 xx 10^(23) MeV`
Correct Answer - `3 xx 10^(7) kg`
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