Assuming 1 metric ton of coal gives heat of combustion equal to 8 kcal and a single fission of `.^(235)U` releases 200 MeV. Calculate the minimum consumption in kg of `.^(235)U` to be heat equivalent ot 100 ton of coal
The chemical equation for the combustion of `C_(2)H_(4)` is
`underset(1" mole")(C_(2)H_(4)(g))+underset("3 moles")(3O_(3)(g))=underset("2 moles")(2CO_(2)(g))+2H_(2)O(l),DeltaU=-335.8kcal`
No. of moles of reactants=(1+3)=4
No. of mols of products=2
So, `Deltan=(2-4)=-2`
Given `DeltaU=-335.8kcal,Deltan=-2,R=2xx10^(-3)kcal`
and `T=(18+273)=291K`
Applying...
We have to calculate of `Delta H` for the reaction
`6 C(s)+3H_(2)(g)rarrC_(6)H_(6)(g)`
For reactant:
Heat of atomisation of `6` moles of `C=6xx170.9 kcal`
heat of atomisation of `6` moles of...