A uranium nucleus `.^(235)U` liberates 200 MeV per fission 1.5 kg of uranium reacts during explosion of a uranium bomb. What is the mass of an equivalent TNT bomb if the heating capacity of TNT is `4.1 xx 10^(6) J//kg` ?
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Calculate the binding energy in MeV of Uranium 238 from the following data Mass of `.^(1)H_(1) = 1.008142 am u`, Mass of `._(0)n^(1) = 1.008982 am u`
Correct Answer - 7.5714 MeV, `13.49 xx 10^(-30) kg`
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When `._(92)U^(235)` undergoes fission, 0.1% of the original mass is released into energy. How much energy is released by an atom bomb which contains
Correct Answer - `9 xx 10^(14)` J
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When an atom of `._(92)U^(235)` undergo fission, about 200 MeV energy is released Suppose that a reactor using `._(92)U^(235)` has an output of 700 MW
Correct Answer - `9.5 xx 10^(24), 3.7` kg
2 Answers 1 views
The `._(92)^(235)U` absorbs a slow neutron (thermal neutron) & undergoes a fission represented by (i) The energy release E per fission. (ii) The energ
Correct Answer - [(i) 200.68 MeV` (ii) `22.86 MWh`]
2 Answers 1 views
Calculate the energy released by `1 g` of natural uranium assuming `200 MeV` is released in eaech fission event and that the fissionable isotope `U^23
Correct Answer - `[5.7 xx 10^(8) J]`
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Assuming 1 metric ton of coal gives heat of combustion equal to 8 kcal and a single fission of `.^(235)U` releases 200 MeV. Calculate the minimum cons
Correct Answer - `[M = 4.077 xx 10^(-8) kg]`
2 Answers 1 views
sion giving 0.1 % of its original mass released as energy. (a) How much energy is released by an atomic bomb that contains `10 kg` of `.^(235)U`. (b)
Correct Answer - `[9 xx 10^(14), 2.25 xx 10^(5) "ton"]`
2 Answers 1 views
Assuming the splitting of `U^235` nucleus liberates `200 MeV` energy, find (a) the energy liberated in the fission of 1 kg of `U^235` and (b) the mass
Correct Answer - [(a) `8.2 xx 10^(10)kJ, 2.7 xx 10^(6) kg` (b) `1.5 g`]
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Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is released by fission of each atom of `.^(235)
Correct Answer - `5.1 xx 10^(23) MeV`
2 Answers 1 views
A reaction develop nuclear energy at the rate of `3 xx 10^(4) kW`. How many atoms of `.^(215)U` undergo fission per second? How much `.^(235)U` is bur
Correct Answer - `9.375 xx 10^(17)`, 1.217 kg
2 Answers 1 views