One g equivalent of Na metal is formed from electrolyis of fused NaCl. No of "mole" of Al from the fused `Na_(3)AlF_(6)` with the same current passed is:
A. 1
B. 3
C. `1//3`
D. `2`
Correct Answer - C
`underset(1" mole")(Na^(+))+underset(1" faraday")(e^(-)to)Na(s)`
`AP^(+)+underset(1" faraday")(3e^(-)to)Al(s)`
No. of mole of `Al=(1)/(3)` mole
Correct Answer - C
`DeltaG^(@) =- "RT In K"_(eq)`
`or,- 1743 = - 8.3 xx300 xx In K_(ep)`
`K_(eq) = 2 =K_(eq) " for reaction 2A"hArr B+C " from given data"`
Sodium cholride (NaCI) is a non-volatile solute, When added to water to taken in a beaker, the solute occupies some surgace are. As a result, the vapour pressure decreses and...
Correct Answer - 7
`underset((A))(3MnO_2)+6KOH+KCIO_3oversetDeltatounderset((B))(3K_2MnO_4)+KCl+3H_2O`
In presence of `CO_2`, the medium becomes acidic.
`3MnO_4^(2-)+4H^(+)toMnO_2 + 2MnO_4^(-)+2H_2O`
`underset((C ))(MnO_4^-)+5Fe^(2+)+8H^(+)toMn^(2+)+5Fe^(3+)+4H_2O`
`MgCl_(2)overset((aq))(to)MgCl^(2)+(aq)+2Cl^(-)(aq)`
`Mg^(2+)(aq)+underset((2xx96500C))(2e)^(-)toMg(s)` (At cathode)
`2xx29500C` of charge deposite MG metal =1mol
`9*65C` of charge deposite Mg metal `=((1mol))/((2xx96500C))xx(9*65C)=5xx10^(-5)mol`
`R-X+underset(1mol)(Mg)("Anhyd. ether")toR-underset(1mol)(MG)-X`
`therefore` No of moles of grignard reagent obtained `=5xx10^(-5)`mol.
