When a quantity of electricity is passed through `CuSO_(4)` solution, 0.16 g of copper gets deposited. If the same quantity of electricity is passed through acidulated water, then the volume of `H_(2)` liberated at STP will be : (given atomic weight of Cu=64)
A. `4 cm^(3)`
B. `56 cm^(3)`
C. `604 cm^(3)`
D. `8 cm^(3)`