A current of 9.95 amp following for 10 minutes, deposits 3 gm of a metal. Equivalent weight of the metal is:
A. 12.5
B. 18.5
C. 21.5
D. 48.5
Correct Answer - C Radioactive disintegration follow `I^(st)` order kinetics `lambda =(l)/(t) ln .(N_(0))/(N_(t)) " " (1)/(45) ln .(100)/(80) =(1)/(t) ln (100)/(64)` `t=45 ((2 ln 10 -6 ln 2)/(ln 10 -3...
2 Answers 1 viewsCorrect Answer - A Q=10x4825 =48250 C no. of mole of `Ag^+ =48250/96500=0.5` `Ag+1/2 Cu^(++)toAg^+ +1/2 Cu` `{:(2.00,2.00),(2-0.25,2+0.50):}` `E_"cell"=E_"cell"^@-0.0591/1 "log" ([Ag^+])/([Cu^(++)]^(1//2)) implies E_1=E_"cell"^@-0.0591/1"log"2.00/((2.00)^1//2)` `E_2=E_"cell"^@-0.0591/1 "log" (2.50)/(1.75)^((1//2)) implies DeltaE=E_2-E_1=0.0591/1["log"sqrt2-"log"2.50/sqrt(1.75)]` `=0.0591/1["log"1.41-"log"1.88]=0.0591/1[0.1492-0.2742]=-0.0591/2xx0.125=-0074 V`
2 Answers 1 viewsCorrect Answer - D Let M is mass of water and P is amount of heat supplied per unit minute. `MS_(W)(100-0) = P xx 10 …..(i)` `ML_(V) = P xx 55...
2 Answers 1 viewsCorrect Answer - A `V = (l tV_(e))/(96500)` `= (1 xx 9650 xx 11.2)/(96500) = 1.12 "litre"`
2 Answers 1 views(a) Using first order kintetic equation and substituting given values In first case: `k=(2.303)/(53)log_(10).(200)/(200-100)=0.0131"min"^(-1)` In second case `k=(2.303)/(100)log_(10).(200)/(200-146)=0.0131"min"^(-1)` As the values of k come out to be the same in...
2 Answers 1 viewsCorrect Answer - `10 W, 5W` `P=iepsilon=[2 sin250pit][10sin(250pit+pi//3)]` at `t=2/3xx10^(-3)rArr P=10 watt` `ltPgt = i_(rms)epsilon_(rms)cos phi=2/sqrt2xx10sqrt2xxcos pi//3` `P=iepsilon=[2sin 250pi t][10 sin (250pit+pi//3)] , t=2/3 xx10^(-3) rArr P=10` watt `ltPgt = i_(rms)epsilon_(rms)cos...
2 Answers 1 viewsCorrect Answer - A Equivalent mass of silver = 108 Equivalent mass of aluminium in `(AlCl_(3))=27/3 =9` `W_(Ag)/W_(Al)=E_(Ag)/E_(Al)` `54/W_(Al)=108/9` `W_(Al)=4.5 g`
2 Answers 1 viewsCorrect Answer - B::D `{:(,3X,+,5YrarrX_(3)Y_(5),,),("Mass","ag",,"ag",,),("Mole",(a)/(36),,(a)/(24),,),("Mole",(a)/(36)xx(1)/(3),,(a)/(24)xx(1)/(5),"Y is the limiting reagent",):}` `therefore " Mass of "X_(3)Y_(5)=(1)/(5)xx((a)/(24))(36xx3+5xx24)=1.9a`
2 Answers 1 viewsCorrect Answer - 1350
2 Answers 1 viewsThe basic aim of the bank is to pool the excess money to the bank and develop the habit of saving amount people. Bank accepts deposits in two forms i.e. Demand...
2 Answers 1 views