A direct current deposits deposits 54 g of silver (Atomic mass = 108) during electrolysis. How much aluminimum (Atomic mass =27) would be deposited from aluminium chloride solution by the same amount of electricity ?
A. 4.5 g
B. 5.4 g
C. 54 g
D. 2.7 g


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Correct Answer - A
Equivalent mass of silver = 108
Equivalent mass of aluminium in `(AlCl_(3))=27/3 =9`
`W_(Ag)/W_(Al)=E_(Ag)/E_(Al)`
`54/W_(Al)=108/9`
`W_(Al)=4.5 g`

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