If the temperature in a room is 30 °C, temperature in degree fahrenheit is
(A) 22 °F
(B) 62 °F
(C) 86 °F
(D) 96 °F
1 Answers
A ball is thrown from a comer of room of length 20 m and height 5 m such that the ball moves along the length of room just touching the ceiling and dr
Correct Answer - (i)`45^(@)` (ii)`10sqrt(2)m//s` (iii) 2 sec
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State the temperatures in Fahrenheit scale that corresponds to 0°C and 100°C.
The temperature that corresponds to 0°C is 32°F and the temperature that corresponds to 100°C is 212°F.
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Write the expression showing the relationship between : i. Degree Fahrenheit and Degree Celsius ii. Kelvin and Degree Celsius
i. The relationship between degree Fahrenheit and degree Celsius is expressed as, °F = \(\frac{9}{5}\)(°C) + 32 ii. The relationship between Kelvin and degree Celsius is expressed as, K = °C + 273.15
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Convert the following degree Fahrenheit temperature to degree Celsius. i. 50 °F ii. 10 °F
Given : Temperature in degree Fahrenheit = 50°F To find : Temperature in degree Celsius Formula : °F = \(\frac{9}{5}\)(°C) + 32 Calculation : Substituting 50°F in the formula, °F = \(\frac{9}{5}\)(°C) + 32 50 = \(\frac{9}{5}\)(°C) + 32 °C = \(\frac{(50-32)\times 5}{9}\) = 10°C ii. Given : Temperature in...
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Calculate the temperature which has the same value on fahrenheit scale and kelvin scale.
Given: TK = TF = x To find: Temperature at which Kelvin and Fahrenheit scales coincide (x) Formula: \(\frac{T_F-32}{180}=\frac{T_K-273.15}{100}\) Calculation: From formula. ∴ \(\frac{x-32}{180}=\frac{x-273.15}{100}\) ∴ 5(x – 32) = 9(x – 273.15) ∴ 5x – 160 = 9x – 2458.35 ∴ 4x...
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The triple points of neon and carbon dioxide are 24.57 K and 216.55 K, respectively. Express these temperatures on the celsius and fahrenheit scales.
Given: For neon, TK = 24.57 K For carbon dioxide, TK = 216.55 K To find: (i) Triple point of neon on celsius (TCN) and fahrenheit scale (TFN) (ii) Triple point of carbon dioxide on Celsius (TCC) and fahrenheit scale...
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The degree of reluctance of a substance to change its temperature
B) specific heat
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If the temperature on Fahrenheit scale is 140 °F, then the same temperature on kelvin scale will be
Correct option is: (C) 333.15 K
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The linear equation that converts Fahrenheit (F) to Celsius (C) is given by the relation C = 5f-160/9
Correct option is (C) 40° For same temperature in both scale, we have to put C = F in the formula \(C=\frac{5F-160}{9}.\) \(\therefore\) \(C=\frac{5C-160}{9}\) \(\Rightarrow\) 9C = 5C - 160 \(\Rightarrow\) 9C - 5C = -160 \(\Rightarrow\) 4C = -160 \(\Rightarrow\) C...
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