Write the expression showing the relationship between : i. Degree Fahrenheit and Degree Celsius ii. Kelvin and Degree Celsius

a. T(K) = t°C +273.15  ∴ T(K) = -15 °C + 273.15  = 258.15 K b. T(K) = t°C +273.15  ∴ T(K) = 25°C + 273.15  = 298.15 K c. T(K) = t°C + 273.15  ∴ T(K)...

The temperature that corresponds to 0°C is 32°F and the temperature that corresponds to 100°C is 212°F.

Given :  Temperature in degree Fahrenheit = 50°F To find :  Temperature in degree Celsius Formula : °F = \(\frac{9}{5}\)(°C) + 32 Calculation :  Substituting 50°F in the formula, °F = \(\frac{9}{5}\)(°C) + 32 50 =  \(\frac{9}{5}\)(°C) + 32 °C = \(\frac{(50-32)\times 5}{9}\)  = 10°C ii. Given :  Temperature in...

Given: TK = TF = x To find: Temperature at which Kelvin and Fahrenheit scales coincide (x) Formula: \(\frac{T_F-32}{180}=\frac{T_K-273.15}{100}\) Calculation: From formula. ∴ \(\frac{x-32}{180}=\frac{x-273.15}{100}\) ∴ 5(x – 32) = 9(x – 273.15) ∴ 5x – 160 = 9x – 2458.35 ∴ 4x...

Given: For neon, TK = 24.57 K For carbon dioxide, TK = 216.55 K To find: (i) Triple point of neon on celsius (TCN) and fahrenheit scale (TFN) (ii) Triple point of carbon dioxide on Celsius (TCC) and fahrenheit scale...

Correct option is  A) 27 K

Correct option is: (C) 86 °F

Correct option is: (C) 333.15 K

Correct option is (C) 40° For same temperature in both scale, we have to put C = F in the formula \(C=\frac{5F-160}{9}.\) \(\therefore\) \(C=\frac{5C-160}{9}\) \(\Rightarrow\) 9C = 5C - 160 \(\Rightarrow\) 9C - 5C = -160 \(\Rightarrow\) 4C = -160 \(\Rightarrow\) C...