Calculate the temperature which has the same value on fahrenheit scale and kelvin scale.

(D) \(\frac{1}{n^2}\) 1 V.S.D. = \(\frac{(n-1)}{n}\) M.S.D. LC. = 1 M.S.D. – 1 V.S.D. = 1 M.S.D. – \(\frac{(n-1)}{n}\) M.S.D. = \(\frac{1}{n}\) M.S.D. = \(\frac{1}{n}\times\frac{1}{n}\) cm ∴ L.C. = \(\frac{1}{n^2}\) cm

The temperature that corresponds to 0°C is 32°F and the temperature that corresponds to 100°C is 212°F.

i. The relationship between degree Fahrenheit and degree Celsius is expressed as, °F = \(\frac{9}{5}\)(°C) + 32 ii. The relationship between Kelvin and degree Celsius is expressed as, K = °C + 273.15

Given :  Temperature in degree Fahrenheit = 50°F To find :  Temperature in degree Celsius Formula : °F = \(\frac{9}{5}\)(°C) + 32 Calculation :  Substituting 50°F in the formula, °F = \(\frac{9}{5}\)(°C) + 32 50 =  \(\frac{9}{5}\)(°C) + 32 °C = \(\frac{(50-32)\times 5}{9}\)  = 10°C ii. Given :  Temperature in...

A) same l value and same n value

Correct option is  A) 27 K

Correct option is  B) 373

Correct option is: (C) 86 °F

Correct option is: (C) 333.15 K

Correct answer is (d) Kelvin