State the temperatures in Fahrenheit scale that corresponds to 0°C and 100°C.
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Let `a_(1), a_(2),….` and `b_(1),b_(2),….` be arithemetic progression such that `a_(1)=25`, `b_(1)=75` and `a_(100)+b_(100)=100`, then the sum of firs
Correct Answer - C `(c )` `(a_(100)+b_(100))-(a_(1)+b_(1))=99dimpliesd=0` `:.` Sum of series `=(100//2)(a_(100)+b_(100)+a_(1)+b_(1))` `=50(100+100)` `=10000`
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The value of `((100),(0))((200),(150))+((100),(1))((200),(151))+......+((100),(50))((200),(200))` equals (where `((n),(r ))="^(n)C_(r)`)
Correct Answer - A `(a)` Writing `((200),(r ))=((200),(200-r))`, we have `((100),(0))((200),(50))+((100),(1))((200),(49))+((100),(2))((200),(48))+......+((100),(50))((200),(0))` `=` Coefficient of `x^(50)` in the expansion of `(1+x)^(100)(x+1)^(200)` `=` Coefficient of `x^(50)` in the binomial expansion of `(1+x)^(300)` `=((300),(50))`
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A scale in a lab measures the mass of object consistently more by 500 g than their actual mass. How would you describe the scale in terms
The scale is precise but not accurate. Explanation: Precision measures how consistently a device records the same answer; even though it displays the wrong value. Hence, the scale is precise. Accuracy is...
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The main scale of a vernier callipers has n divisions/cm. n divisions of the vernier scale coincide with (n – 1) divisions of main scale.
(D) \(\frac{1}{n^2}\) 1 V.S.D. = \(\frac{(n-1)}{n}\) M.S.D. LC. = 1 M.S.D. – 1 V.S.D. = 1 M.S.D. – \(\frac{(n-1)}{n}\) M.S.D. = \(\frac{1}{n}\) M.S.D. = \(\frac{1}{n}\times\frac{1}{n}\) cm ∴ L.C. = \(\frac{1}{n^2}\) cm
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Write the expression showing the relationship between : i. Degree Fahrenheit and Degree Celsius ii. Kelvin and Degree Celsius
i. The relationship between degree Fahrenheit and degree Celsius is expressed as, °F = \(\frac{9}{5}\)(°C) + 32 ii. The relationship between Kelvin and degree Celsius is expressed as, K = °C + 273.15
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Calculate the temperature which has the same value on fahrenheit scale and kelvin scale.
Given: TK = TF = x To find: Temperature at which Kelvin and Fahrenheit scales coincide (x) Formula: \(\frac{T_F-32}{180}=\frac{T_K-273.15}{100}\) Calculation: From formula. ∴ \(\frac{x-32}{180}=\frac{x-273.15}{100}\) ∴ 5(x – 32) = 9(x – 273.15) ∴ 5x – 160 = 9x – 2458.35 ∴ 4x...
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The triple points of neon and carbon dioxide are 24.57 K and 216.55 K, respectively. Express these temperatures on the celsius and fahrenheit scales.
Given: For neon, TK = 24.57 K For carbon dioxide, TK = 216.55 K To find: (i) Triple point of neon on celsius (TCN) and fahrenheit scale (TFN) (ii) Triple point of carbon dioxide on Celsius (TCC) and fahrenheit scale...
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Which of the following thermometer scale is also known as absolute scale of temperature?
C) Kelvin scale
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On celsius scale, the two fixed points are marked as (A) 0°C and 232°C (B) 32°C and 100°C (C) 0°C and 100°C
Correct option is: (C) 0°C and 100°C
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If the temperature on Fahrenheit scale is 140 °F, then the same temperature on kelvin scale will be
Correct option is: (C) 333.15 K
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