If CH3 – CH2 – CH2 – COOH is the IUPAC structure of carbon compound, then the carbon compound is
A) Butene
B) Butanol
C) Butanoic acid
D) But – 1 – ene
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Identify type of the intermolecular forces in the following compounds. a. CH3 – OH b. CH2 = CH2 c. CHCl3
a. Hydrogen bonding (dipole-dipole attraction) and London dispersion forces b. London dispersion forces c. Dipole-dipole interactions and London dispersion forces d. Dipole-dipole interactions and London dispersion forces
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For the complex `K_(2)[Cr(NO)(NH_(3))(CN)_(4)],mu=1.73 BM`. (i) Write IUPAC name. (ii) What will be structure ? (iii) How many unpaired electrons are
Correct Answer - (i) potassium amminetetracyanidonitrosoniumchromate(I) (ii) Octahedral (iii) One unparied electron (iv) It is paramagnetic with one unpaired electron (v) `EAN=24-1+2xx6=35` (iv) `d^(2)sp^(3)`
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2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2 Compare the structure of the substrate propanol with that of the product sodium propoxide.
In above reaction, The -OH group of the substrate molecule has undergone a change. The H-atom of hydroxyl group (-OH) is replaced by sodium forming the product.
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Butanol — i) CH3 -CH2 -CH2 -CH2 -COOH , Pentanoic acid — ii) CH3– CH2 – CH2– CH2 – CH2 – CHO
C) a → iii,b → i,c → iv,d → ii
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HO – CH2 – CH2 – CH2 – COOH.
D) 4 – hydroxy -1 – butanoic acid
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CH3 – NH – CH3 is known as
C) secondary amine
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If the carbon compound has many functional groups, then the order of preference while naming according to IUPAC nomenclature is
B) — COOH >CONH2 > CHO NH2
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NH2 – CH2 – CHOH – CH2 – COOH is
C) 4 – amino – 3 – hydroxy butanoic acid
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CH3 — CH2 — OH reacts with alkaline KMnO4 and heats to form first the compound A, which futher oxidises to form a compound B.
Correct option is D) Acetic acid
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There are 3 isotopes of carbon. Carbon-12, Carbon-13 and Carbon-14. The most abundant carbon isotope is carbon – 12.
Correct option is A) 12.01
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