The IUPAC name of
NH2 – CH2 – CHOH – CH2 – COOH is
A) 1 – amino – 2 hydroxy butanoic acid
B) 3 – hydroxy – 4 – amino butanoic acid
C) 4 – amino – 3 – hydroxy butanoic acid
D) 1 – amino – 3 – hydroxy butyric acid
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Identify type of the intermolecular forces in the following compounds. a. CH3 – OH b. CH2 = CH2 c. CHCl3
a. Hydrogen bonding (dipole-dipole attraction) and London dispersion forces b. London dispersion forces c. Dipole-dipole interactions and London dispersion forces d. Dipole-dipole interactions and London dispersion forces
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The product P of the following reaction is `CH_(3)-COOH overset(LiAlH_(4))to overset(SOCl_(2))to overset(Koverset(14)(C)N)to overset(H_(3)O^(o+)) to P
Correct Answer - `CH_(3)-CH_(2)-overset(14)(C)OOH`
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`CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) overset(H_(2)//Pd//BaSO_(4))to(Z) overset(OH^(-))t
Correct Answer - `X=Cl_(3)C-underset(O)underset(||)(C)-OH,Y=Cl_(3)C-underset(O)underset(||)(C)-Cl,Z=Cl_(3)C-underset(O)underset(||)(C)-H,W=CHCl_(3),S=HCOO^(Theta)`
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2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2 Compare the structure of the substrate propanol with that of the product sodium propoxide.
In above reaction, The -OH group of the substrate molecule has undergone a change. The H-atom of hydroxyl group (-OH) is replaced by sodium forming the product.
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Butanol — i) CH3 -CH2 -CH2 -CH2 -COOH , Pentanoic acid — ii) CH3– CH2 – CH2– CH2 – CH2 – CHO
C) a → iii,b → i,c → iv,d → ii
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—NH2 group is called …………….
Correct option is C) amine
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HO – CH2 – CH2 – CH2 – COOH.
D) 4 – hydroxy -1 – butanoic acid
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If CH3 – CH2 – CH2 – COOH is the IUPAC structure of carbon compound, then the carbon compound is
C) Butanoic acid
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UPAC name of Cl3C – CH2 – CHO
A) 3, 3, 3 – trichloro propanal
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CH3 — CH2 — OH reacts with alkaline KMnO4 and heats to form first the compound A, which futher oxidises to form a compound B.
Correct option is D) Acetic acid
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