2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2 Compare the structure of the substrate propanol with that of the product sodium propoxide.

Question

2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2 Compare the structure of the substrate propanol with that of the product sodium propoxide.

Consider the following reaction :

2CH₃ – CH₂ – CH₂ – OH + 2Na → 2CH₃ – CH₂– CH₂ – ONa + H₂

Compare the structure of the substrate propanol with that of the product sodium propoxide. Which part of the substrate, the carbon skeleton or the OH group has undergone a change during the reaction?

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Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

In above reaction,

The -OH group of the substrate molecule has undergone a change.

The H-atom of hydroxyl group (-OH) is replaced by sodium forming the product.

2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2 Compare the structure of the substrate propanol with that of the product sodium propoxide.

1 Answers