CH3 — CH2 — OH reacts with alkaline KMnO4 and heats to form first the compound A, which futher oxidises to form a compound B.

a. Hydrogen bonding (dipole-dipole attraction) and London dispersion forces  b. London dispersion forces  c. Dipole-dipole interactions and London dispersion forces  d. Dipole-dipole interactions and London dispersion forces

In above reaction, The -OH group of the substrate molecule has undergone a change.  The H-atom of hydroxyl group (-OH) is replaced by sodium forming the product.

C) a → iii,b → i,c → iv,d → ii

D) 4 – hydroxy -1 – butanoic acid

C) secondary amine

C) Butanoic acid

C) 4 – amino – 3 – hydroxy butanoic acid

i. KMnO4 Oxidation number of K = +1  Oxidation number of O = -2  KMnO4 is a neutral molecule.  ∴ Sum of the oxidation numbers of all atoms = 0  ∴ (Oxidation number of K)...

Correct option is D) Diffusion

Correct option is: (C) 1, 3, 4, 5