The volume (V) of a mass of gas varies directly as its absolute temperature (T) and inversely as the pressure (P) applied to it. The gas occupies a vo

PV=nRT M.F= `(SF_(4))_(x)` `(1.02)xx22xx10^(-3)` `(0.1)/((108)x)xx0.0821xx293` `x=(0.1xx0.0821xx293)/((108)(1.02)(22.1)xx10^(-3))=1` M.F. `=SF_(4)`

Correct Answer - `102^(@)C`

Option : b. 11.2 dm3

Given :  V1 = Initial volume = 600 mL,  V2 = Final volume = 640 mL P1 = Initial pressure = 760 mm Hg  T1 = Initial temperature = 25°C  = 25 + 273.15 K =...

Correct Answer - ` 4500 pi cm^(3)`

Correct Answer - 125 K

At temperature of -273.15°C, the volume of the gas will be ideally zero.

(A) \(CO_2\) Let say, the molar mass of unknown gas is M Then, Number of mole of unknown gas = \(\frac{4.4\,g}{M}\) As we know, 1 mole of any gas at STP occupy = 22.4 L of volume. \(\therefore\) Number of...

Given: V0 = 2 × 10-4 m3, T0 = 0°C,T = 80°C, γr = 4 × 10-4 K-1, T – T0 = 80 – 0 = 80°C To find: Increase in volume (∆V) Formula: ∆V = V0γr(T – T0) Calculation: From formula. ∆V =...