4.4 g of an unknown gas occupies 2.24 L of volume under STP conditions. The gas may be ………………

Monjur Alahi

4.4 g of an unknown gas occupies 2.24 L of volume under STP conditions. The gas may be ………………

(A) CO2

(B) CO 

(C) O2 

(D) SO2


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Salim Ahmed Kawsar

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(A) \(CO_2\)

Let say, the molar mass of unknown gas is M

Then, Number of mole of unknown gas = \(\frac{4.4\,g}{M}\)

As we know,

1 mole of any gas at STP occupy = 22.4 L of volume.

\(\therefore\) Number of moles unknown gas = \(\frac{2.24}{22.4}=0.1\) mol

Therefore,

\(\frac{4.4}{M}=0.1\)

\(M=\frac{4.4}{0.1}\)

M = 44 g/mol

In the given options only \(CO_2\) has molar mass of 44 g/mol

Hence, the unknown gas will be \(CO_2\).

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Salim Ahmed Kawsar

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Option : (A) CO2

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