4.4 g of an unknown gas occupies 2.24 L of volume under STP conditions. The gas may be ………………
(A) CO2
(B) CO
(C) O2
(D) SO2
Given : V1 = Initial volume = 600 mL, V2 = Final volume = 640 mL P1 = Initial pressure = 760 mm Hg T1 = Initial temperature = 25°C = 25 + 273.15 K =...
2 Answers 1 viewsCorrect Answer - ` (700)/3 K`
2 Answers 1 viewsCorrect Answer - ` 4500 pi cm^(3)`
2 Answers 1 viewsCorrect Answer - 125 K
2 Answers 1 viewsCorrect Answer - 20.1
2 Answers 4 viewsGiven : Volume of ammonia at STP = 67.2 dm3 To find : Number of moles and molecules of ammonia Formulae : i. Number of moles of a gas (n) = \(\frac{Volume\,of\,\,a\,gas\,at\,STP}{Molar\,volume\,of\,a\,gas}\) ii. Number of molecules =...
2 Answers 6 viewsGiven : Mass of ammonia = 3.40 g Volume at STP = 4.48 dm3 To Find : Molar mass of ammonia Calculation : Let ‘x’ grams be the molar mass of NH3. Molar volume of a gas...
2 Answers 3 views(A) \(CO_2\) Let say, the molar mass of unknown gas is M Then, Number of mole of unknown gas = \(\frac{4.4\,g}{M}\) As we know, 1 mole of any gas at STP occupy = 22.4 L of volume. \(\therefore\) Number of...
2 Answers 1 viewsGiven: V0 = 2 × 10-4 m3, T0 = 0°C,T = 80°C, γr = 4 × 10-4 K-1, T – T0 = 80 – 0 = 80°C To find: Increase in volume (∆V) Formula: ∆V = V0γr(T – T0) Calculation: From formula. ∆V =...
2 Answers 1 viewsCorrect option is B) i and iv
2 Answers 1 views