A mass of gas exerts a pressure of `72 cm` of Hg at `27^(@)C`. It is heated at constant volume so that its pressure after some time is `90 cm` of Hg. Calculate the new temperature of the gas.
Correct Answer - B
We know that , `DeltaH=DeltaE+pDeltaV`
When, `DeltaV=0`
`therefore DeltaH=DeltaE`
In given problem `DeltaH=500 J `
`-W=-pDeltaV,DeltaV=0`
So, `DeltaE=q=500 J`
(i) `C_(P)-C_(V)=(R)/(M)` where, M=molecular of gas
`0.125-0.075=(1.987)/(M)`
`M=39.74~~40`
(ii) `(C_(P))/(C_(V))=gamma`
`therefore=(0.125)/(0.075)=1.66`
`therefore` 1.66 value of `gamma` shows that the gas is monoatomic.