calculate the energy released in the nuclear fusion of isotopes of hydrogen
(i) `._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n`
(ii) `._(1)^(2)H + ._(1)^(3)H rarr ._(2)^(4)He + ._(0)^(1)n`
Given that mass of neutron = 1.00867 amu
`{:("mass of",._(1)^(2)H = 2.01410,am u,),("mas of",._(1)^(3)H = 3.01603,am u,),("mass of ",._(2)^(3)H = 3.0160,am u,),("mass of ",._(2)^(4)He = 4.00260,am u,):}`


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Correct Answer - (i) 3.26 MeV , (ii) 17.6 MeV