Calculate the energy that can be obtained from 1 kg of water through the fusion reaction
`H^2+H^2 rarr H^3 +p`.
Assume that `1.5xx10^(-2)%`of natural water is heavy water `D_2 O`(by number of molecules ) and all the deuterium is used for fusion.
(i) The half reaction are :
`2Ag^(+)+underset(("Reduction"),("(Cathode)"))(2e^(-)) rarr 2Ag`,
`E_(Ag^(+)//Ag)^(@)=0.80` volt (Reduction potential)
`Cd rarr underset(("Oxidation"),("(Anode)"))(Cd^(2+))+2e^(-)`,
`E_(Cd^(2+)//Cd)^(@)=-0.40` volt (Reduction potential)
or `E_(Cd//Cd^(2+))^(@)=+0.40` volt
`E^(@)=E_(Cd//Cd^(2+))^(@)+E_(Ag^(+)//Ag)^(@)=0.40+0.80=1.20` volt
(ii) The negative electrode is...
Net charge `=2.5xx10^(-7) -2.5xx10^(-7)=0`
Electric dipole moment, `P = ("Magnitude of charge")xx("Separation between charges")`
`=2.5xx10^(-7) [0.15+0.15]C m =7.5xx10^(-8) Cm`
the direction of dipole moment is from B to A.
Nuclear fusion involves the fusion of lighter nuclei to form a heavy nucleus which is accompanied by an enormous amount of energy (heat).
Fusion reaction requires extremely high temperature typically of...