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When a hydrogen atom is excited from ground state to first excited state then

Monjur Alahi

When a hydrogen atom is excited from ground state to first excited state then
A. its kinetic energy increases by `10.2 eV`
B. its kinetic energy decreases by `13.6 eV`
C. its potential energy increases by `10.2 eV`
D. its angular momentum increases by `h//2pi`


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Salim Ahmed Kawsar

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Correct Answer - D
In ground state , kinetic energy `= 13.6 eV`, Potential energy `= -27.2 eV`
In first excited state, kinetic energy `= 3.4 eV`, Potential energy `= - 6.8 eV`
Angular momentum momentum is `= (nh)/(2pi)` , Difference of angular momentum for consecutinve orbit `= (h)/(2pi)`

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A photon of energy `12.09 eV` is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is

Correct Answer - C Energy difference in hydrogen atom `= 13.6 - (13.6)/(n^(2)) = 12.09 rArr n^(2) ~~ 9 rArr n = 3`

2 Answers 2 views
An electron collides with a dfixed hydrogen atom in its ground stat. Hydrogen atom gets excited and the collding electron loses all its kinetic energy

Correct Answer - 2 Kinetic energy of electron `= 13.6 [1-1/9] eV = 12.1 eV`.

2 Answers 1 views
A photons was absorbed by a hydrogen atom in its ground state, and the elctron was prompted to the fifth orbit. When the excited atom returuned to its

Correct Answer - D `N= .^(n)C_(2) = .^(5)C_(2) = 10`

2 Answers 1 views
An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the r

Correct Answer - B `E_(1) = (hc)/(lambda) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` For second excited state to first excited state `E_(1) = (hc)/(lambda) [1/4 - 1/9] rArr (hc)/(lambda) ((5)/(36))` For first excited state...

2 Answers 1 views
A particular hydrogen like atom has its ground state Binding energy `= 122.4 eV`. It is in ground state. Then

Correct Answer - A::C::D `122.4 = (13.6Z^(2))/(1^(2)) rArr Z = 3, 91.8 = 122.4[1-(1)/(4)]` So an electron of KE `91.8 eV` can transfer its energy to this atom.

2 Answers 1 views
In a hydrogen atom, the electron is in `n^(th)` excited state. It may come down to second excited state by emitting ten different wavelengths. What is

Correct Answer - A `10= .^(n)C_(2) implies n=5`, then 5 orbits are involved upon coming to second excited state so `n^(th)` excited state is `6^(th) [2^(nd), 3^(rd), 4^(th), 5^(th), 6^(th)]`

2 Answers 1 views
An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energ

Correct Answer - C Excitation upto `n=3` is required so that visible length is emitted upon de-excitation. So required energy `=13.6 (1-1/9)=12.1 eV`

2 Answers 1 views
Calculate the energy required to excited one litre of hydrogen gas at `1` atm and `298 K` to the excited state of atomic hydrogen. The energy for the

Correct Answer - B Mole of `H_(2)` present in one litre `=(PV)/(RT)=(1xx1)/(0.0821xx298)=0.0409` Thus, energy needed to break H-H bonds in `0.0409` mole `H_(2)=0.0409xx436=17.83 kJ`. Also energy needed to excite one H...

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A hydrogen like atom (atomic number = Z) is in higher excited state of quantum number n. This excited atom can make a transition to first excited stat

Correct Answer - `n = 7 ; Z = 3`

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Correct Answer - `20 eV, 13.2 eV`

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