A hydrogen like atom (atomic number = Z) is in higher excited state of quantum number n. This excited atom can make a transition to first excited state by successively emitting two photons of energy `22.94 eV` and `5.15 eV`. The atom from the same state n can make transition to second excited state by successively emitting two photons of energies `2.4 eV` and `8.7 eV`. Find values of n and Z.
1 Answers
A photon of energy `12.09 eV` is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is
Correct Answer - C Energy difference in hydrogen atom `= 13.6 - (13.6)/(n^(2)) = 12.09 rArr n^(2) ~~ 9 rArr n = 3`
2 Answers 2 views
When a hydrogen atom is excited from ground state to first excited state then
Correct Answer - D In ground state , kinetic energy `= 13.6 eV`, Potential energy `= -27.2 eV` In first excited state, kinetic energy `= 3.4 eV`, Potential energy `= -...
2 Answers 2 views
An electron collides with a dfixed hydrogen atom in its ground stat. Hydrogen atom gets excited and the collding electron loses all its kinetic energy
Correct Answer - 2 Kinetic energy of electron `= 13.6 [1-1/9] eV = 12.1 eV`.
2 Answers 1 views
An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the r
Correct Answer - B `E_(1) = (hc)/(lambda) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` For second excited state to first excited state `E_(1) = (hc)/(lambda) [1/4 - 1/9] rArr (hc)/(lambda) ((5)/(36))` For first excited state...
2 Answers 1 views
In a sample of `H-` atom electrons make transition from `5^(th)` excited state to ground state, producing all possible types of photons, then number o
Correct Answer - C Infrared lines =total lines -visible lines -UV lines `=(6(6-1))/(2)-4-5 =15-9=6` `("visible lines" =4 6 rarr2, 5 rarr2, 4 rarr 2, 3 rarr 2)` " " `("UV lines"...
2 Answers 1 views
Find the quantum of the excited state of electrons in `He^(+)` ion which on transition to first excited state emit photons of wavelengths `108.5 nm`.
Correct Answer - B `1/lambda=R_(H)Z^(2)[1/1^(2)-1/n_(2)^(2)]` `1/(108.5xx10^(-9))=1.09678xx10^(7)xx4[1/2^(2)-1/n_(2)^(2)]` This gives `n_(2)=5`
2 Answers 1 views
Calculate the energy required to excited one litre of hydrogen gas at `1` atm and `298 K` to the excited state of atomic hydrogen. The energy for the
Correct Answer - B Mole of `H_(2)` present in one litre `=(PV)/(RT)=(1xx1)/(0.0821xx298)=0.0409` Thus, energy needed to break H-H bonds in `0.0409` mole `H_(2)=0.0409xx436=17.83 kJ`. Also energy needed to excite one H...
2 Answers 1 views
`H^(+)` ions are in excited state from where maximum 6 types of photons can be emitted. If E is the separation energy of electron in this excited stat
Correct Answer - 4 `6=(n(n-1))/(2)" "n=4` Separation energy, `E=+13.6 xx(z^(2))/(n^(2))=+13.6xx((2)^(2))/((4)^(2))=3.4 eV` l.E. of Hydrogen atom `=x xxE=13.6 eV` `x=(13.6)/(E)=4`
2 Answers 2 views
Hydrogen like atoms (atomic number `= Z`) in a sample are in excited state with principal quantum number n. The emission spectrum of the sample has `1
Correct Answer - `Z = 3`
2 Answers 3 views
An electron in an excited hydrogen atom makes transition from a state of quantum number n to a state of quantum number `(n – 1)`. (a) Show that the fr
Correct Answer - (b) The two are same
2 Answers 1 views