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A particular hydrogen like atom has its ground state Binding energy `= 122.4 eV`. It is in ground state. Then

Monjur Alahi

A particular hydrogen like atom has its ground state Binding energy `= 122.4 eV`. It is in ground state. Then
A. Its atomic number is 3
B. An electrom of `90` eV cam excite it
C. An electron of kinetic energy nearly `91.8 eV` can be brought to almost rest by this atom
D. An electron of kinetic energy `2.6 eV` may emerge from the atom when electron of kinetic energy 125 eV collides with this atom


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Salim Ahmed Kawsar

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Correct Answer - A::C::D
`122.4 = (13.6Z^(2))/(1^(2)) rArr Z = 3, 91.8 = 122.4[1-(1)/(4)]`
So an electron of KE `91.8 eV` can transfer its energy to this atom.

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An electron of a hydrogen like atom is in excited, state. If total energy of the electron is -4.6 eV, then evaluate (i) the kinetic energy and (ii) th

Given ,total energy of the electron `E=-4.6 EV` (i) Kinetic energy of electron K=-(Total energy E,) `rArr " " =-E=-(-4.6)=4.6 eV` (ii) de- Brogile wavelength `lambda_(d)=(h)/(sqrt(2 mK))=(6.6xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx4.6xx1.6xx10^(-19)))` `0.57xx10^(-9)m=0.57 nm`

2 Answers 2 views
The energy of the electron in the ground state of hydrogen atom is `-13.6 eV`. Find the kinetic energy and potential energy of electron in this state.

Correct Answer - B Kinetic energy of electron in ground state =-(Totoal energy in this state) `" " --(13.6 )eV=13.6 eV`

2 Answers 1 views
If `13.6eV` energy is required to separate a hydrogen atom into a proton and an electron, then the orbital radius of electron in a hydrogen atom is

Correct Answer - A Here, `E=-13.6eV=-13.6xx1.6xx10^(-19)=-2.2xx10^(-18)J` `E=(-e^2)/(8piepsilon_0r)` `therefore` As orbital radius, `r=(-e^2)/(8piepsilon_0E)=(9xx10^(9)xx(1.6xx10^(-19))^2)/(2xx(2.2xx10^(-18)))=5.3xx10^(-11)m`.

2 Answers 1 views
An electron collides with a dfixed hydrogen atom in its ground stat. Hydrogen atom gets excited and the collding electron loses all its kinetic energy

Correct Answer - 2 Kinetic energy of electron `= 13.6 [1-1/9] eV = 12.1 eV`.

2 Answers 1 views
A photons was absorbed by a hydrogen atom in its ground state, and the elctron was prompted to the fifth orbit. When the excited atom returuned to its

Correct Answer - D `N= .^(n)C_(2) = .^(5)C_(2) = 10`

2 Answers 1 views
An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the r

Correct Answer - B `E_(1) = (hc)/(lambda) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` For second excited state to first excited state `E_(1) = (hc)/(lambda) [1/4 - 1/9] rArr (hc)/(lambda) ((5)/(36))` For first excited state...

2 Answers 1 views
An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energ

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2 Answers 1 views
If the binding energy of `2^(nd)` excited state of a hydrogen like sample os `24 eV` approximately, then the ionisation energy of the sample is approx

Correct Answer - D `(13.6(Z)^(2))/((3)^(2))=24` I.E. `=13.6(Z)^(2)=(24xx9)=216 ev`

2 Answers 1 views
A free hydrogen atom in its ground state is at rest. A neutron having kinetic energy `k_(0)` collides head one with the atom. Assume that mass of both

Correct Answer - (a) `20.4 eV` , (b) `8.72 eV` or `4.19 eV`

2 Answers 1 views
A hydrogen atom in ground state is moving with a kinetic energy of 30 eV. It collides with a deuterium atom in ground state at rest. The hydrogen atom

Correct Answer - `20 eV, 13.2 eV`

2 Answers 1 views

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