An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energy. Consequently the hydrogen atom may emit a photon corresponding to the largest wavelength of the Balmer series. The K.E. of colliding electron will be
A. `10.2 eV`
B. `1.9 eV`
C. `12.1 eV`
D. `13.6 eV`


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Correct Answer - C
Excitation upto `n=3` is required so that visible length is emitted upon de-excitation.
So required energy `=13.6 (1-1/9)=12.1 eV`