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A photons was absorbed by a hydrogen atom in its ground state, and the elctron was prompted to the fifth orbit. When the excited atom returuned to its

Monjur Alahi

A photons was absorbed by a hydrogen atom in its ground state, and the elctron was prompted to the fifth orbit. When the excited atom returuned to its ground state, visible and other quanta were emitted. In this process, how many maximum spectral lined could be obtained-
A. 1
B. 2
C. 5
D. 10


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Salim Ahmed Kawsar

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Correct Answer - D
`N= .^(n)C_(2) = .^(5)C_(2) = 10`

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A photon of energy `12.09 eV` is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is

Correct Answer - C Energy difference in hydrogen atom `= 13.6 - (13.6)/(n^(2)) = 12.09 rArr n^(2) ~~ 9 rArr n = 3`

2 Answers 2 views
When a hydrogen atom is excited from ground state to first excited state then

Correct Answer - D In ground state , kinetic energy `= 13.6 eV`, Potential energy `= -27.2 eV` In first excited state, kinetic energy `= 3.4 eV`, Potential energy `= -...

2 Answers 2 views
An electron collides with a dfixed hydrogen atom in its ground stat. Hydrogen atom gets excited and the collding electron loses all its kinetic energy

Correct Answer - 2 Kinetic energy of electron `= 13.6 [1-1/9] eV = 12.1 eV`.

2 Answers 1 views
An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the r

Correct Answer - B `E_(1) = (hc)/(lambda) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` For second excited state to first excited state `E_(1) = (hc)/(lambda) [1/4 - 1/9] rArr (hc)/(lambda) ((5)/(36))` For first excited state...

2 Answers 1 views
In a hydrogen atom, the electron is in `n^(th)` excited state. It may come down to second excited state by emitting ten different wavelengths. What is

Correct Answer - A `10= .^(n)C_(2) implies n=5`, then 5 orbits are involved upon coming to second excited state so `n^(th)` excited state is `6^(th) [2^(nd), 3^(rd), 4^(th), 5^(th), 6^(th)]`

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An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energ

Correct Answer - C Excitation upto `n=3` is required so that visible length is emitted upon de-excitation. So required energy `=13.6 (1-1/9)=12.1 eV`

2 Answers 1 views
In a sample of `H-` atom electrons make transition from `5^(th)` excited state to ground state, producing all possible types of photons, then number o

Correct Answer - C Infrared lines =total lines -visible lines -UV lines `=(6(6-1))/(2)-4-5 =15-9=6` `("visible lines" =4 6 rarr2, 5 rarr2, 4 rarr 2, 3 rarr 2)` " " `("UV lines"...

2 Answers 1 views
Find the quantum of the excited state of electrons in `He^(+)` ion which on transition to first excited state emit photons of wavelengths `108.5 nm`.

Correct Answer - B `1/lambda=R_(H)Z^(2)[1/1^(2)-1/n_(2)^(2)]` `1/(108.5xx10^(-9))=1.09678xx10^(7)xx4[1/2^(2)-1/n_(2)^(2)]` This gives `n_(2)=5`

2 Answers 1 views
A hydrogen like atom (atomic number = Z) is in higher excited state of quantum number n. This excited atom can make a transition to first excited stat

Correct Answer - `n = 7 ; Z = 3`

2 Answers 1 views
A hydrogen atom in ground state is moving with a kinetic energy of 30 eV. It collides with a deuterium atom in ground state at rest. The hydrogen atom

Correct Answer - `20 eV, 13.2 eV`

2 Answers 1 views

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